-16t^2+66t+2=0

Solution for -16t^2+66t+2=0 equation:

-16t^2+66t+2=0

a = -16; b = 66; c = +2;
Δ = b2-4ac
Δ = 662-4·(-16)·2
Δ = 4484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4484}=\sqrt{4*1121}=\sqrt{4}*\sqrt{1121}=2\sqrt{1121}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-2\sqrt{1121}}{2*-16}=\frac{-66-2\sqrt{1121}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+2\sqrt{1121}}{2*-16}=\frac{-66+2\sqrt{1121}}{-32}
$